-7x^2-14+560=0

Solution for -7x^2-14+560=0 equation:

-7x^2-14+560=0

We add all the numbers together, and all the variables

-7x^2+546=0

a = -7; b = 0; c = +546;
Δ = b2-4ac
Δ = 02-4·(-7)·546
Δ = 15288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15288}=\sqrt{196*78}=\sqrt{196}*\sqrt{78}=14\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{78}}{2*-7}=\frac{0-14\sqrt{78}}{-14}
=-\frac{14\sqrt{78}}{-14}
=-\frac{\sqrt{78}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{78}}{2*-7}=\frac{0+14\sqrt{78}}{-14}
=\frac{14\sqrt{78}}{-14}
=\frac{\sqrt{78}}{-1}
$